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lianna [129]
3 years ago
5

How many valence electrons are in Tr2-

Chemistry
2 answers:
myrzilka [38]3 years ago
8 0

Answer:

4 valence electrons

Explanation:

Vikki [24]3 years ago
7 0
Tellurium belongs to the group 6 which is also the group of oxygen which has 6 valence electrons.
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Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
How are chemical and mechanical weathering the same?
sasho [114]

Answer:

They break down materials into smaller pieces

Explanation:

Although using different methods

8 0
3 years ago
What is the ph of a 0.45 m solution of aniline (c6h5nh2)? (pkb  9.40)?
mote1985 [20]

Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+ H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).

pKb(C₆H₅NH₂) = 9.40.

Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.

c₀(C₆H₅NH₂) = 0.45 M.

c(C₆H₅NH₃⁺) = c(OH⁻) = x.

c(C₆H₅NH₂) = 0.45 M - x.

Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).

4·10⁻¹⁰ = x² /  (0.45 M - x). 

Solve quadratic equation: x = c(OH⁻) = 0.0000134 M.

pOH = -log(0.0000134 M.) = 4.87.

pH = 14 - 4.87 = 9.13.

7 0
3 years ago
Which angles are right
Citrus2011 [14]
Right angle acute angle obtuse angle
5 0
3 years ago
Read 2 more answers
How many moles is 573.28 g of AgCl?
g100num [7]

Answer:

4 moles

Explanation:

First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.

7 0
3 years ago
Read 2 more answers
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