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Alex787 [66]
3 years ago
10

Which of the following paths correctly displays the transfer of energy for sound?

Physics
2 answers:
galben [10]3 years ago
8 0
Energy source to detection to medium
makvit [3.9K]3 years ago
5 0

Answer:

the energy source, the transfer of energy through a medium,

Explanation:

The three parts of sound consist of the energy source, the transfer of energy through a medium, and the detection of the sound.

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Three identical balls are thrown from the same height off a tall building. They are all thrown with the same speed, but in diffe
koban [17]

Answer:

three balls have the same speed

Explanation:

In a parabolic motion we have that

v_{x}=v_{0}cos\alpha\\v_{y}=-gt+v_{0}sin\alpha\\v=\sqrt{v_{x}^{2}+v_{y}^{2}}\\

but the time just before the balls hit the ground is

t=\frac{2v_{0}sin\alpha}{g}

Hence we have

ball A

v=\sqrt{v_{0}^{2}cos^{2}(0)+(-g\frac{2v_{0}sin(0)}{g}+v_{0}sin(0))^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball B

v=\sqrt{v_{0}^{2}cos^{2}(45)+(-g\frac{2v_{0}sin(45)}{g}+v_{0}sin(45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball C

v=\sqrt{v_{0}^{2}cos^{2}(-45)+(-g\frac{2v_{0}sin(-45)}{g}+v_{0}sin(-45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

Hence, all three balls have the same speed just before hit the groug

vA=vB=vC

I hope this is useful for you

regards

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i dont know for real

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