Answer:
Explanation:
Given that the force of the particle is,
Now it can be further written as
Now the initial conditions are v=1 at t=0.
So,
Now the velocity will become.
And,
And, another initial condition is x=0 at t=0
Now,
Answer:
sorry but what can u speak english
Capacity of the gas tank . . . Liters
Distance to the next town . . . Kilometers
Smaller units would produce bigger numbers.
It's best to use the units that produce the handiest, most convenient numbers. That way, it's easier to remember the number, write it down without mistakes, and tell other people about it.
Answer:
E_aprox = 1.003 E_real
Explanation:
In this exercise we are given the expression for the electric field of a dipole in the axis direction of the dipole
E_real = k 2q d / √(z² + d²)³
I think your equation has some errors.
In this case they indicate that d is the separation of the charges of the dipole
in the case of z »d this equations approximates
E_aprox = k 2q d/ z³
calculate the value for the two cases
E_real = k2q d / √[ ((23d)² + d²)³]
E_real = k2q d / d³ 12201
E_real = k2q 1/12201 d²
E_aprox = k2q d / (23.00d)³
E_aprox = k2q 1/12167 d²
the error between these quantities is
E_aprox / E_real = 12201 d² / 12167 d²
E_aprox / E_real = 1.003
E_aprox = 1.003 E_real