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The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d
Rydberg's formula :
,
where λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from to
and
= 109677 is the Rydberg Constant. Here
and
represents the transitions.
(a) =2 to
= infinity
= 109677/4 [since 1/infinity = 0] Therefore,
= 4 / 109677 = 0.00003647 m
(b) =4 to
= 20
= 6580.62
Therefore, = 1 / 6580.62 = 0.000152 m
(c) =3 to
= 10
= 11089.56
Therefore, = 1 / 11089.56 = 0.00009 m
(d) =2 to
= 1
= - 82257.75
Therefore, = 1 /82257.75 = - 0.0000121 m
[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]
So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.
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is most abundant and 6310 times more than HF.
When an acid is dissolved in water, all of its molecules disintegrate, making the acid powerful.
When an acid is dissolved in water, only a small number of its molecules disintegrate, making the acid weak. Strong acids have a lower pH than weak acids.
The powerful acids include perchloric acid, chloric acid, nitric acid, sulfuric acid, hydrobromic acid, and hydroiodic acid.
Given:
Pka=3..2
pH=7
Let the volume be 1 liter
[HF]=01 M
Now,
F-:HF= 6309.57:1
Therefore, the most abundant is and has 6310 times more than HF is
.
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