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Veronika [31]
4 years ago
12

Ron weasley isn't the best experimentalist. after an experiment he ends up with only 3.10 g of product. however, the same reacti

on has is a theoretical yield of 3.50 grams of product. what is the percent yield?
Chemistry
1 answer:
Veronika [31]4 years ago
4 0
The experiment should theoretically yield 3.50 g of the product.
However during the experiment it can yield only 3.10 g of the product.
actual yield is lesser than the theoretical yield, therefore we need to find the percentage yield.
Percentage yield can be calculated using the following equation 
Percent yield = \frac{actual  yield}{theoretical yield}  * 100%
Percent yield = 3.10 g / 3.50 g x 100% = 88.6%
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Explain why world food shortages could be reduced by growing more algae.
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8 0
3 years ago
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Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

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2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)

2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)

On adding above equations, we get the following combined equation.

2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn

We need 0.0392 grams of Zn metal to completely reduce vanadium.

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