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3 years ago

Maria said that you can blu always separate a mixture by filtration. Is she correct?

Chemistry

2 answers:

Olegator [25]3 years ago

8 0

Yes because it’s true

Temka [501]3 years ago

4 0

Explanation:

Filtration works best when the solute isn't dissolve in the solvent. For instance, sand and water can be seperate through filtration as both compounds do not dissolve with each other. However, sugar and water would not be seperated through filtration as they dissolve with each other.

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The movement of charged particles cannot pass through an electrolyte to produce an electric current.

Rus_ich [418]

The movement of charged particles cannot pass through an electrolyte to produce an electric current.

True

False

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3 years ago

How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *

galben [10]

Answer:

52.5 mol O2

Explanation:

4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2

4 mol FeCl3 -> 6 mol O2

35.0 mol FeCl3 -> x

x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3

x=52.5 mol O2

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3 years ago

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How small are the microorganisms that live on and in the human body? Answer it in at least 1 paragraph

Lera25 [3.4K]

Answer:

The human body contains trillions of microorganisms — outnumbering human cells by 10 to 1. Because of their small size, however, microorganisms make up only about 1 to 3 percent of the body's mass (in a 200-pound adult, that's 2 to 6 pounds of bacteria), but play a vital role in human health.

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3 years ago

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Can i have help with this ???

Andreas93 [3]

Answer:

section 2

Explanation:

it has the shiny silver apperance but at the same time is hard and brittle

8 0

2 years ago

Tap water at room temperature has a pH of 7.2 and carbonate alkalinity of 200 mg/L (= 40 mmol/L). What is the concentration of b

UNO [17]

Answer:

the concentration of bicarbonate is [HCO₃⁻] = 0,03996 M and carbonate is [CO₃²⁻] = 3,56x10⁻⁵ M.

Explanation:

Carbonate-bicarbonate is:

HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25

Using Henderson-Hasselbalach formula:

pH = pka + log₁₀ $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$

7,2 = 10,25 + log₁₀ $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$

8,91x10⁻⁴ = $\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}$ (1)

Also:

0,040 M = [CO₃²⁻] + [HCO₃⁻] (2)

Replacing (2) in 1:

[HCO₃⁻] = 0,03996 M

Thus:

[CO₃²⁻] = 3,56x10⁻⁵ M

I hope it helps.

4 0

3 years ago