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2 years ago

Why don't atoms get too close?

Physics

2 answers:

ipn [44]2 years ago

6 0

I think C i’m sorry i don’t really pay attention to this anymore as I learned it in 6th

Lera25 [3.4K]2 years ago

3 0

Answer:

I would have to go with A, or maybe....yea A

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What is the volume of an object that has Mass=100g and Density= 745g/mL.

lana66690 [7]

Answer:0.13ml

Explanation:

6 0

3 years ago

For the long life cells we have to connect them in ____ combination

NISA [10]

Answer:

Parallel combination.

5 0

3 years ago

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The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?

Nina [5.8K]

It is the photosphere

5 0

3 years ago

Aconstant current of 3 Afor 4 hours is required to charge an automotive battery. If the terminal voltage is V, where t is in hou

kirza4 [7]

Answer:

(a) 43.2 kC

(b) 0.012V kWh

(c) 0.108V cents

Explanation:

<u>Given:</u>

i = current flow = 3 A
t = time interval for which the current flow = $4\ h = 4\times 3600\ s = 14400\ s$
V = terminal voltage of the battery
R = rate of energy = 9 cents/kWh

<u>Assume:</u>

Q = charge transported as a result of charging
E = energy expended
C = cost of charging

Part (a):

We know that the charge flow rate is the electric current flow through a wire.

$\therefore i = \dfrac{Q}{t}\\\Rightarrow Q =it\\\Rightarrow Q = 3\times 14400\\\Rightarrow Q = 43200\ C\\\Rightarrow Q = 43.200\ kC\\$

Hence, 43.2 kC of charge is transported as a result of charging.

Part (b):

We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

$E = Vit\\\Rightarrow E = V\times 3\times 4\\\Rightarrow E = 12V\ Wh\\\Rightarrow E = 0.012V\ kWh\\$

Hence, 0.012V kWh is expended in charging the battery.

Part (c):

We know that the energy cost is equal to the product of energy expended and the rate of energy.

$\therefore \textrm{Cost}=\textrm{Energy}\times \textrm{Rate}\\\Rightarrow C = ER\\\Rightarrow C = 0.012V\times 9\\\Rightarrow C =0.108V\ cents$

Hence, 0.108V cents is the charging cost of the battery.

4 0

4 years ago

87) Determine the equivalent resistances for the following circuits.

stepladder [879]

Answer:

15 and 11 ohms

Explanation:

First one = For the parallel resistors 1 / (1/6 + 1/6 + 1/6) = 1/ (3/6 ) = 6/3 = 2 ohms then add the 3 and the 10 = 15 ohms

second one for the parallel portion equiv = (10+2)*24 / ( (10+2 + 24) = 8

then add the 3 in series = 11 ohms

8 0

2 years ago