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iragen [17]
3 years ago
8

Bob is pushing a box across the floor at a constant speed of 1.2 m/s, applying a horizontal force whose magnitude is 75 N. Alice

is pushing an identical box across the floor at a constant speed of 2.4 m/s, applying a horizontal force.
What is the magnitude of the force that Alice is applying to the box?
F = N
Physics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:75 N

Explanation:

Given

Bob is pushing the box with a force of 75 N with constant speed. Constant speed indicates that net force on the block is zero i.e. friction force is balancing the applied force.

so friction force f=75 N

If Alice is pushing an identical box with constant speed so net force acting on box must be equal to an applied force.

As the friction force is 75 N so Alice must be applying a force of 75 N  

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Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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Given that,

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(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

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Put the value of Φ in equation (I)

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(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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