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iragen [17]
3 years ago
8

Bob is pushing a box across the floor at a constant speed of 1.2 m/s, applying a horizontal force whose magnitude is 75 N. Alice

is pushing an identical box across the floor at a constant speed of 2.4 m/s, applying a horizontal force.
What is the magnitude of the force that Alice is applying to the box?
F = N
Physics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:75 N

Explanation:

Given

Bob is pushing the box with a force of 75 N with constant speed. Constant speed indicates that net force on the block is zero i.e. friction force is balancing the applied force.

so friction force f=75 N

If Alice is pushing an identical box with constant speed so net force acting on box must be equal to an applied force.

As the friction force is 75 N so Alice must be applying a force of 75 N  

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Answer:

   x = 9.32 cm

Explanation:

For this exercise we have an applied torque and the bar is in equilibrium, which is why we use the endowment equilibrium equation

Suppose the counterclockwise turn is positive, let's set our reference frame at the left end of the bar

          - W l / 2 - W_{child} x + N₂ l = 0

             x = \frac{-W l/2 + n_2 l}{W_{child}}             1)

now let's use the expression for translational equilibrium

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we substitute

           N₁ - W - W_child + 4 N₁ = 0

           5 N₁ -W - W_{child} = 0

           N₁ = ( W + W_{child}) / 5

         

we calculate

           N₁ = (450 + 250) / 5

          N₁ = 140 N

           

we calculate with equation 1

           x = -250 1.50 + 4 140 3) / 140

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