What is the percent composition of calcium (Ca) in CaO?
2 answers:
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Answer:- 123 amu.
Solution:- The formula to calculate the average atomic mass of an atom is:
Average atomic mass = mass of first isotope(abundance of first isotope) + mass of second isotope(abundance of second isotope)
Note: The percent abundance is converted to decimals.
mass of Sb-121 is 121 amu and it's percent abundance is 57.3% and in decimal it is 0.573. Percent abundance of Sb-123 is 42.8% and in decimal it is 0.428. We are asked to calculate it's mass. The average atomic mass of Sb is given as 122.
Let's say the mass of Sb-123 is M and plug in the values in the formula and do calculations:
122 = 121(0.573) + M(0.428)
122 = 69.333 + M(0.428)
On rearrangement:-
M(0.428) = 122 - 69.333
M(0.428) = 52.667
M = 123
So, the mass of Sb-123 is 123 amu.
Answer : The resonance structure of is shown below.
Explanation :
Resonance structure : It is defined as when more than one Lewis structure can be drawn, the molecule or ion is said to have resonance.
Resonance is the concept where electrons (bonds) are delocalized over three or more atoms which cannot be depicted with one simple Lewis structure.
First we have to draw Lewis-dot structure.
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
As we know that sulfur has '6' valence electrons, carbon has '6' valence electrons and nitrogen has '5' valence electron.
Therefore, the total number of valence electrons in = 6 + 4 + 5 = 15
According to Lewis-dot structure, there are 7 number of bonding electrons and 8 number of non-bonding electrons.
In SCN, carbon atom is the central atom and sulfur and nitrogen are the neighboring atoms.
The resonance structure of is shown below.
