Question

a garden has an area of 304ft^2 . its length is 3 ft more than its width. what are the dimensions of the garden?

Answer 1

Answer:

W = 16 feet

L  = 19 feet

Step-by-step explanation:

We'll assume this is a rectangular garden.

Let L and W be the width and length, respectively.

W*L = Area = 304 ft^2

L = W + 3

Use this last expression in the first:

W*L = 304 ft^2

W*(W+3) = 304 ft^2

W^2+3W = 304 ft^2

W^2+3W - 304 ft^2 = 0

W = 16 and - 19.  We'll assume we're in the current galaxy, so we can ignore the - 19 feet.

W = 16 feet

L = 304ft^2/16ft = 19 feet