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3 years ago

Which type of surface would best reflect light?

Chemistry

2 answers:

marishachu [46]3 years ago

8 0

Answer:

Honestly I would guess D

Explanation:

sorry if im wrong

andrew11 [14]3 years ago

3 0

You are correct the answers is D

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The p-value of a statistical test depends on all of the following, except:

vaieri [72.5K]

Answer:

The correct option is e.

Explanation:

p-value is the probability value for a given statistical model, the probability that, when the null hypothesis is true.

For two two samples the formula of test statistics is

$t=\frac{(\overline{x}_1-\overline{x}_2)-(\mu_1-\mu_2)}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}$

where,

$\overline{x}$ is sample mean

$\mu$ is population mean.

$s$ is standard deviation.

n is sample size.

Variance is the square of standard deviation.

It means variance, mean, numbers of samples is used in calculation of p-value.

Degree of freedom define the shape of the t-distribution that your t-test uses to calculate the p-value.

$d.f.=n_1+n_2-2$

p-value of a statistical test depends on all of the following, except median.

Therefore the correct option is e.

4 0

3 years ago

How do I convert units the easiest

damaskus [11]

To convert among units in the metric system, identify the unitthat you have, the unit that you want to convert to, and then count the number of units between them. If you are going from a larger unit to a smaller unit, you multiply by 10 successively

7 0

4 years ago

A) 30.22 g NaCl x 1 mol NaC l = 58.4430 Molar mass (g) NaCl=0.5171 mol NaCl

jekas [21]

The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.

So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.

6 0

3 years ago

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

<u>Answer:</u> The density of gold in $g/cm^3$ is $19.22g/cm^3$

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

6 0

4 years ago

Refer to the two formulas for xylose.

Ludmilka [50]

Answer:

A is the molecular formula for xylose because shows the actual number of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the molecular formula for xylose because shows the arrangement of atoms in the compound: Formula B is the structurab formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the empirical formula for xylose because it shows the actual number of atoms in the compound: Formula B is the molecular formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the structural formula for xylose because it shows the arrangement of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound.

5 0

3 years ago