Answer:
ΔTb = 0.66 C
Explanation:
Given
Mass of KBr = 185 g
Mass of water = 1.2 kg
Kb = 0.51 C/m
Explanation:
The change in boiling point (ΔTb) is given by the product of molality (m) of the solution and the boiling point constant (Kb)


[tex]\Delta T_{b}= 0.51 C/m * 1.296 m = 0.66 C[\tex]
Answer:
your question is totally wrong. there is no cl2 in reactants.
It’s c 1.59 x 10^4L i’m positive