Answer:
The answer to your question is: C₂H₆O₁ = C₂H₆O
Explanation:
Data
CxHyOz
mass = 40 g produced 76.40 g of CO2
46.96 g of H2O
Empirical formula = ?
Process
CxHyOz + O2 ⇒ CO2 + H2O
44g of CO2 -------------------- 12 g of Carbon
76.40 g of CO2 --------------- x
x = 20.84 g of Carbon
12 g of Carbon --------------- 1 mol
20.84 g of C --------------- x
x = (20.84 x 1) / 12
x = 1.74 mol of Carbon
18 g of H2O -------------------- 2 g of H
46.96 g of H2O -------------- x
x = (46.96 x 2) / 18
x = 5.22 g of H
1 g of H ------------------------ 1 mol of H
5.22 g of H ------------------- x
x = 5.22 mol of H
Mass of Oxygen = 40 - 20.84 - 5.22g
= 13.94 g
16 g of Oxygen ---------------- 1 mol
13.94 g of O -------------------- x
x = 0.87 mol of O
Divide by the lowest number of moles
Carbon = 1.74 / 0.87 = 2
Hydrogen = 5.22 / 0.87 = 6
Oxygen = 0.87 / 0.87 = 1
Empirical formula
C₂H₆O₁ = C₂H₆O
