Select True or False: The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol. Bloom's Level: Understand

Chemistry

1 answer:

MissTica1 year ago

7 0

True, the entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.

The third law of thermodynamics states that, the entropy of a system approaches a constant value as the temperature of the system approaches absolute zero.

The entropy of any perfectly ordered, crystalline substance at absolute zero temperature is zero. That is, the entropy of a pure, perfect crystalline substance at 0 K is 0 J/K.

Thus, we can conclude that the given statement is true. The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.

Learn more about third law of thermodynamics here: brainly.com/question/1156831

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2 years ago

1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?

tatyana61 [14]

<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

10.0 M HNO₃

Prepared solution;

Volume of solution as 0.350 L
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2 years ago

Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO

zavuch27 [327]

Answer:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Explanation:

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In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

$2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons 4NOBr ( g )$