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3 years ago

9

Use the periodic table to identify the number of core electrons and the number of valence electrons in each case below.Magnesium

(Mg): 1s22s22p63s2

2 answers:

ser-zykov [4K]3 years ago

7 0

Answer:

10 core 2 valence

Explanation:

i just did this question on edgenuity

andrey2020 [161]3 years ago

3 0

Answer:

10 core electrons 2 valence electrons

Explanation:

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A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is t

netineya [11]

Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 15.0mL

V2 = ?

P1 = 760 torr

P2 = 1252 torr

T1 = 10°C = 10 + 273 = 283K

T2 = 35°C = 35 + 273 = 308K

Using P1V1/T1 = P2V2/T2

760 × 15/283 = 1252 × V2/308

11400/283 = 1252V2/308

Cross multiply

11400 × 308 = 283 × 1252V2

3511200 = 354316V2

V2 = 3511200 ÷ 354316

V2 = 9.91 mL

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3 years ago

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Alexeev081 [22]

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3 years ago

What are the Number of molecules of 14 grams of NO2

algol [13]

6.022 x 1023 atoms are in 14 grams of NO2

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55 L of a gas at 25oC has its temperature increased to 35oC. What is its new volume?

ladessa [460]

Answer:

Approximately 56.8 liters.

Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.

Explanation:

Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}$ ,

where

$V_2$ is the final volume,
$V_1$ is the initial volume,
$T_2$ is the final temperature in degrees Kelvins.
$T_1$ is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

$T_1 = \rm 25^{\circ}C = (25 + 273.15)\; K = 298.15\; K$ .

$T_2 = \rm 35^{\circ}C = (35 + 273.15)\; K = 308.15\; K$ .

Apply Charles's Law to find the new volume of this gas:

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 55\;L \times \frac{308.15\; K}{298.15\; K} = 56.8\; L$ .

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In the name, iron(III) oxide, the (III) represents

miss Akunina [59]

Answer:

A

Explanation:

the number o iron atoms

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