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3 years ago

9

Use the periodic table to identify the number of core electrons and the number of valence electrons in each case below.Magnesium

(Mg): 1s22s22p63s2

2 answers:

ser-zykov [4K]3 years ago

7 0

Answer:

10 core 2 valence

Explanation:

i just did this question on edgenuity

andrey2020 [161]3 years ago

3 0

Answer:

10 core electrons 2 valence electrons

Explanation:

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Stels [109]

Answer:

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4 years ago

A gas starts out with a volume of 114 liters and temperature of 273 K. The volume then increases to 216 liters. If the pressure

Yuri [45]

Answer:

517.3 K

Explanation:

Initial volume of gas V1= 114 L

Initial temp. T1= 273 K

Final volume V2= 216 L

Final temp. T2= ?

From Charles law, Volume is directly proportional to temperature provided pressure is kept constant

V1/T1 = V2/T2

T2 = V2T1/V1

T2 = (216×273)/114

T2 = 517.3 K

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4 years ago

A NaOH solution is standardized using the monoprotic primary standard potassium hydrogen phthalate, KHP (204.22 g/mol.) If 0.698

kakasveta [241]

Answer:

0.07789 M is the sodium hydroxide concentration.

Explanation:

Mass of potassium hydrogen phthalate = 0.6986 g

Molar mass of potassium hydrogen phthalate = 204.22 g/mol

Moles of potassium hydrogen phthalate = $\frac{0.6986 g}{204.22 g/mol}=0.003421 mol$

$NaOH+KHP\rightarrow NaKP+H_2O$

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

$\frac{1}{1}\times 0.003421 mol=0.003421 mol$

Moles of NaOH = 0.003421 mole

Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

$Concentration=\frac{Moles}{Volume(L)}$

Concentration of NaOH :

$\frac{0.003421 mol}{0.04392 L}=0.07789 M$

0.07789 M is the sodium hydroxide concentration.

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3 years ago

Define the clinical thermometer

Sloan [31]

Answer:

a small medical thermometer with a short but finely calibrated range, for taking a person's temperature.

6 0

3 years ago

Read 2 more answers

How many moles of co2 are produced when 5.40 mol of ethane are burned in an excess of oxygen?

Nimfa-mama [501]

<span>Reaction of ethane combustion:

2C2H6 (g) + 7O2 (g) ----> 4CO2 (g) + 6H2O

According to the reaction, we can see that </span>C2H6 and CO2 have following stoichiometric ratio:

n(C2H6) : n(CO2) = 2 : 4

If we know the number of moles of ethane we can calculate moles of carbon dioxide:

2 x n(CO2) = 4 x n(C2H6)

n(CO2) = 2 x n(C2H6)

n(CO2) = 2 x 5.4 = 10.8 mole of CO2 <span>are produced</span>

3 0

4 years ago