Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:
where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,
<u>r = 0.05 m = 5 cm</u>
Answer:
linear charge density = -9.495 × C/m
Explanation:
given data
revolutions per second = 1.80 ×
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 × ×
q = m × w² × r ............2
and w =
w =
w = 1.80 × ×
w = 11304000 rad/s
so here from equation 2
- 9 × ×
1.80 ×
= 1.672 ×
× 11304000² × 0.0120
linear charge density = -9.495 × C/m