If the PLATE SEPARATION of an isolated charged parallel-plate capacitor is doubled: A. the electric field is doubled
1 answer:
Explanation:
The electric field of an isolated charged parallel-plate capacitor is given by :
........(1)
Where
q is the electric charge
A is the area of cross section of parallel plate
It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.
So, the correct option is (E) i.e. "none of the above".
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Answer:
a = 0.45 m/s²
Explanation:
The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".
Given that,
Force, F = 40 N
Mass of the body, m = 88 kg
The net force acting on the body is given by :
F = ma
Where
a is the acceleration of the body
So, the required acceleration is 0.45 m/s².