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Serggg [28]
3 years ago
13

An object is moving in a circle. If the radius of the object is doubled, and the period remains constant, the magnitude of the v

elocity will be ___ original value.
Physics
1 answer:
Anton [14]3 years ago
4 0

Answer:

Twice

Explanation:

From the formula for velocity in a circle

V= 2πr/T

Where V is velocity

r is raduis

T is period

We see that as r increases V increases so if r is doubled V becomes doubled

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Which statement correctly explains scientific theories?
Elan Coil [88]
<span>Scientific theories are tested and proven over time; they are then considered scientific laws.

Sometimes however, they are proven wrong, and so they do not become laws

hope this helps</span>
4 0
3 years ago
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17. _______ is a fuel produced by fermenting crops.
DENIUS [597]
Fuel is produced by fermenting Ethanol
6 0
3 years ago
Which of these processes are chemical reactions
White raven [17]

Explanation:

  • In chemical reactions, chemical changes occur.
  • Atoms are simply rearranged and new bonds are formed.
  • Chemical reactions are driven by a need for atoms to attain stability in their structure.
  • In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
  • Most these reactions are not easily reversible.
  • They are usually accompanied by the release of energy.

Learn more:

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5 0
3 years ago
The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC
enyata [817]

Answer:

The y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

Explanation:

<u>Given:</u>

  • Electric field in the region, \vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.
  • Charge placed into the region, q = 10.4\ nC = 10.4\times 10^{-9}\ C.

where, \hat i,\ \hat j are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.

Thus, the y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

3 0
3 years ago
A power cycle operates between a lake’s surface water at a temperature of 300 K and water at a depth whose temperature is 285 K.
nikdorinn [45]

Answer: a) 0.04kW = 40W

b) 0.05

Explanation:

A)

Thermal efficiency of the power cycle = Input / output

Input = 10 kW + 14,400 kJ/min = 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.

Output = 10 kW

Thermal Efficiency = Output / Input = 10kW / 250kW = 0.04KW = 40W

B)

Maximum Thermal Efficiency of the power cycle = 1 - T1/T2

Where T1 = 285kelvin

And T2 = 300kelvin

Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05

8 0
4 years ago
Read 2 more answers
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