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Ymorist [56]
3 years ago
7

_________ acceleration occurs when an object speeds up.

Physics
2 answers:
Angelina_Jolie [31]3 years ago
7 0

Positive acceleration occurs when an object speeds up.

Explanation:

Acceleration is the rate of change in velocity per unit time:

a=\frac{\Delta v}{\Delta t}

where \Delta v is the change in velocity while \Delta t is the time interval. From the formula, we can understand that when \Delta v is positive, so when the object is speeding up, the acceleration is positive; on the contrary, when \Delta v is negative (so, when the object is slowing down), the acceleration is negative.

fiasKO [112]3 years ago
7 0

The Positive acceleration of a body is the acceleration that speeds up the object under acceleration.

Explanation:

The acceleration of a body is a vector quantity that requires the direction along with the magnitude for its representation. The acceleration of a body is defined as the change in velocity per unit time of the body under the motion.

The direction of acceleration helps in determining whether the body will speed up or its speed will decrease during the motion under the acceleration.

If the direction of acceleration of the body is in the direction opposite to the motion of the body, then this acceleration of body will reduced the velocity of the object.

On the other hand, if the direction of acceleration of the body is same as the direction in which the body is moving, then it will speed up the object during the motion.

<em>The acceleration of the body acting in the direction opposite to the motion of the body is called as the negative acceleration whereas the acceleration of the body along the direction of motion of the body is termed as the positive acceleration.</em>

Thus, The Positive acceleration of a body is the acceleration that speeds up the object under acceleration.

Learn More:

1. Minimum coefficient of the static friction between feet and floor brainly.com/question/1621778

2. To calculate broadcast wavelength of radio station: brainly.com/question/9527365

3. Stress in the bungee cord: brainly.com/question/12985068

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, speed, velocity, positive, speeds up, direction, opposite, along, motion, reduce, increase.

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Rom4ik [11]
<span>The correct option is D. Soil can best be described as the loose covering of weathered rocks and decaying organic matter. There are different types of soil, the type of soil formed depends majorly on the type of parent rock from which the soil is formed and the amount of organic matter present in the soil.</span>
5 0
3 years ago
how much force would be required to produce 88 j of work when pushing a box 1.1meters at an angle of 10 degrees?
ycow [4]

Answer:81.235N

Explanation:

Work=88J

theta=10°

distance=1.1 meters

work=force x cos(theta) x distance

88=force x cos10 x 1.1 cos10=0.9848

88=force x 0.9848 x 1.1

88=force x 1.08328

Divide both sides by 1.08328

88/1.08328=(force x 1.08328)/1.08328

81.235=force

Force=81.235

5 0
3 years ago
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
3 years ago
An object weighing 49 N is dropped from a height of 30 m. It is found to be moving with a velocity of 24m/s just before it hits
faltersainse [42]

The  frictional force will be 0.22N.

<h3>What is Frictional force?</h3>

Frictional force is the force generated between two surfaces that are in contact and slide against each other.

Given,

Weight=4N

mass =4.9/9.8=0.5kg

Hieght =30m

velocity=24m/s

Acceration , v²-u²=2as

24²/2×30 =a , u is zero

 a= 1.5m/s²



By Using conservation  of energy ,

30F+1/2mv²=mgh

30F=1150-144

F= 6/30

F=0.2N

The force will be 0.2N

to learn more about Friction clickhttps://brainly.com/question/17608236

#SPJ9

6 0
2 years ago
Projectile motion in two dimensions cannot be determined by breaking the problem into two connected one-dimensional problems.
andriy [413]
The answer I believe is False
8 0
3 years ago
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