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KATRIN_1 [288]
3 years ago
9

What is kelvin scale?

Physics
2 answers:
Darina [25.2K]3 years ago
4 0
<span>a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees.</span>
Alborosie3 years ago
4 0
It's a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees
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A slender, uniform metal rod of mass M and length lis pivoted without friction about an axis through its midpoint andperpendicul
lys-0071 [83]

Answer:

Explanation:

Moment of inertia of the metal rod pivoted in the middle

= M l² / 12

If the spring is compressed by small distance x twisting the rod by angle θ

restoring force by spring

= k x

moment of torque  about axis

= k x l /2

= k θ( l /2 )²     ( x / .5 l = θ )

=

moment of torque = moment of inertia of  rod  x angular acceleration

k θ( l /2 )²   = M l² / 12 d²θ/dt²

d²θ/dt² = 3 k/M  θ

acceleration =  ω² θ

ω² = 3 k/M

ω = √ 3 k / M

8 0
3 years ago
Read 2 more answers
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natka813 [3]
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5 0
3 years ago
What are 2 ways organisms would be affected by water pollution?
Ymorist [56]
Not having clean water to drink or bath. Also some organizations that live in the water might die because the water is polluted and that would be toxic form them
7 0
3 years ago
A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.
worty [1.4K]

F= ma; a= F/m

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4 0
3 years ago
A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
Luda [366]

Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

3 0
3 years ago
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