(3,6). 3 units from point. 6 units from y axis.
-8.1
Step-by-step explanation:
<em>Times </em><em>all </em><em>by </em><em>9</em><em> </em><em>to </em><em>get </em><em>rid </em><em>of </em><em>fraction</em>
<em></em>
<em>Take </em><em>2</em><em>1</em><em>.</em><em>6</em><em> </em><em>away</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>sides</em>
<em></em>
<em>Divide</em><em> </em><em>by </em><em>-</em><em>4</em>
<em></em>
Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
Answer is:
x ≥ -18/5
2+4/9x ≥ 4+x
4/9x-x ≥4-2
4/9x-9/9x ≥2
- 5/9x ≥2 multiple by 9
-5x ≥2•9
-5x ≥18
x ≥ -5/18
Answer:
The second graph
Step-by-step explanation: