C because they are both going in a constant speed
From Literature:
The amount of energy in the photons is given by this equation:
E = hf
where E = energy
h = Planck's constant = 6.63 * 10^-34 Joule seconds
f = frequency of the light, Hz
Given:
E= 3.00 eV and Planck's constant
To solve for the frequency, E = 3.00 eV
1 electronvolt = 1.60218 x 10^-19 Joules
3 * 1.60218 x 10^-19 Joules = 6.63 * 10^-34 Joule seconds * f
f = 7.25 x 10^14 /second or hertz
Therefore, the threshold frequency of the material is 7.25 x 10^14 Hertz.
Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V
Given;
redistivity =1.68/100000000W.m
diameter =0.40in
=0.01016m
length =1m
resistance =?
redistivity =resistance×area/lenght
restance=resistivity × length /area
so, resistance =1.6535/1000000 ohmn
Power = work / time --> time = work / power = 3600 J / 275 watts = 13.1 seconds.
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