For this case we have the following expression:
(x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
Rewriting we have:
(((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
Then, we cancel similar terms:
((x + 1) / (x-4)) / (1 / (x + 4))
Rewriting:
((x + 1) (x + 4)) / (x-4)
Answer:
((x + 1) (x + 4)) / (x-4)
Answer:
The number of calculators is 4871
Step-by-step explanation:
If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.
the result of the integration is:
to be evaluated between 3 and 5, which is:
Answer:
He can take 5 Horses at max in his trailer at one time without going over the max weight his truck can tow. (Assuming the average weight of one horse to be equal to 1000 pounds)
Step-by-step explanation:
The no. of horses that can be carried by the truck can be found by simply dividing the maximum weight, that the truck can tow by the weight of a horse.
Max. No of Horses = (Max weight truck can tow)/(Average weight of one horse)
The weight of a horse is not given in the question .Thus, we assume the average weight of one horse, to be equal to 1000 pounds, we get:
Max. No of Horses = 5000 pounds/ 1000 pounds
<u>Max. No of Horses = 5</u>
No 3/7 do not represents the same length on the number line
