Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.
Answer:
6 : 1
Step-by-step explanation:
b - 3a / 9 = a /3
Cross multiply
3(b - 3a) = 9a
Expand
3b - 9a = 9a
Add 9a to both sides
3b = 9a + 9a
3b = 18a
Divide both sides by 3
b = 6a
Ratio of a : b
6 : 1
Answer:
i guess it's option d sorry if wanted someone else to answer
Answer:
I'm pretty sure it's 90%
Step-by-step explanation:
Answer:
7y
Step-by-step explanation:
use distributive property:
4x+12y=6x-2y
2x=14y
x=7y
