The number of Pbr3 that contain 3.68 x10^ 25 bromine atoms is 60.631 moles
calculation
by use of Avogadro law constant
that is, 1 moles = 6.02 x10^23 atoms
what about 3.65 x10^25 atoms
by cross multiplication
= (1 mole x 3.65 x 10 ^25 atoms) / ( 6.02 x10^23 atoms) = 60.631 moles
atoms and atoms cancel out each other
Leading zeros
Captive zeros
Trailing zeros
Answer:
i think it is all atoms of all elements are exactly alike and have the same mass
Explanation:
I don’t understand the question
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2 cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius
