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padilas [110]
3 years ago
6

B) A 120.0 g sample of ice at -10.0°C has placed on a heat source. How much energy must be

Chemistry
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

Q = 27060 j

Explanation:

Given data:

Mass of sample = 120 g

Initial temperature = -10.0 °C

Final temperature = 100 °C

Heat added = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T₂ - T₁

ΔT = 100- (-10)

ΔT = 110°C

Q = m.c. ΔT

Q = 120 g × 2.05 g/J.°C × 110°C

Q = 27060 j

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As per as the Multiplication rules of the significant figures, whenever any numbers in the decimals forms are multiplied or divided then result in mentioned in such a way so that the significant figures after the decimal will be same as that in the given least condition.


_______________________________


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