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Degger [83]
3 years ago
14

How many mL of a .132 M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt?

Chemistry
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

465mL

Explanation:

Volume of a solution, V =Mass of substance, m/(Molarity of the solution of the substance, M × molar mass of the substance, M.m)

Given in the question,

M=.132M

M.m=23+35.5 = 58.5g/mol

m=3.59g

V= 3.59/(.132×58.5)

V = 0.465L

Volume in mL = volume in L × 1000

= 0.465 × 1000 = 465mL

Therefore, 465mL of a .132M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt

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