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topjm [15]
3 years ago
9

Which term best describes the type of bonding in magnesium chloride

Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0
Ionic would be the answer
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A student sets up the following equation to convert a measurement. The (?) Stands for a number the student is going to calculate
Vika [28.1K]

Answer:

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}  

Explanation:

0.030 cm³ × ? = x m³

You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.

For example, you know that centi means "× 10⁻²", so  

1 cm = 10⁻² m

If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).

If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.

So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.

We choose the former because it has the desired units on top.

The "cm" is cubed, so we must cube the conversion factor.

The calculation becomes

\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 0.30 \times 10^{-6}\text{ m}^{3} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}\\\\\textbf{0.30 cm}^{\mathbf{3}} \times \left (\dfrac{\mathbf{10^{-2}}\textbf{ m}}{\textbf{1 cm}}\right )^{\mathbf{3}} = \mathbf{3.0 \times 10^{-7}} \textbf{ m}^{\mathbf{3}}

7 0
3 years ago
PLEASE HELP MEEEE<br> Africa<br><br> Asia (India)<br><br> Australia<br><br> Europe
stellarik [79]

Answer:

Australia is correct

Explanation:

Because it is not attached to any other place

3 0
3 years ago
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Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is
tankabanditka [31]

Answer:

M_{A} : M_{B}  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = \pir^{2}h

For cylinder A, l_{A} = h_{A} = \frac{1}{4} l_{B} and r_{A} = 4r_{B}.

Volume of cylinder A = \pi(4r_{B}) ^{2} × \frac{1}{4} l_{B}

                                   = 4\pir_{B} ^{2} l_{B}

Volume of cylinder B =  \pi(r_{B}) ^{2} l_{B}

                                  =  \pir_{B} ^{2}l_{B}

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = \frac{M}{V}

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }

density of B = \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

⇒            \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }  =  \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

The ratio of mass of cylinder A to that of B is given as;

                       \frac{M_{A} }{M_{B} }  =  \frac{4\pi r_{B} ^{2} l_{B}  }{\pi r_{B} ^{2} l_{B}  }

⇒                        \frac{M_{A} }{M_{B} } = \frac{4}{1}

Therefore, M_{A} : M_{B}  = 4 : 1

8 0
3 years ago
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PLEASE HELP MEEEEEEE An equal force is used to push several blocks of different sizes across a table. The time it takes for the
Karolina [17]
It will be c as none of the others make semse
6 0
3 years ago
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Can someone help me and tel me the answer pls its urgent
netineya [11]

Answer:

what do u need help with?

Explanation:

5 0
3 years ago
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