Answer:
OptionA, Insulin
Explanation:
Steroids are organic compound having four fused ring arranged in specific configuration. The four fused rings are composed of 17 carbons.
Most common example of steroids includes Cholesterol, steroids hormones and bile salts.
Among given options, all are steroids except insulin.
Insulin is an endocrine hormone and released from pancreas. It is a non-steroid hormone.
Androgens and estrogens are sex hormones whereas cholesterol is a waxy substance present in blood plasma and animal tissues.
In Bohr's atomic model, the electrons are orbiting outside in orbitals around the nucleus. The farther the electron is from the nucleus, the lower its energy level becomes. That is why when reactions occur, it is the valence electrons (outermost electrons) that gets involve in the bonding. The way you write an electronic configuration is how the energy levels decreases. The first is orbital 1s which is the highest energy level because it is nearest to the nucleus. Then, it is followed by 2s2p, and so on and so forth. The energy levels are represented by the numbers.
When electrons transfer from orbital to orbital, they may release (high to low) or absorb (low to high) energy in the form of light which can be measuredin wavelength. The formula to be used is Rydberg's formula:
1/λ = R(1/n₁² - 1/n₂²), where
λ is wavelength measured in meters
n₁ and n₂ are the energy levels such that n₂>n₁
R is the Rydberg constant equal to 1.097×10⁷ m⁻¹
1/λ =1.097×10⁷ m⁻¹ (1/2² - 1/4²)
λ = 4.86×10⁻⁷ or 4.86 pm
Answer:
One kind is called living things. Living things eat, breathe, grow, move, reproduce and have senses. The other kind is called nonliving things. Nonliving things do not eat, breathe, grow, move and reproduce.
Answer:
\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}
Explanation:
Hello,
The suitable differential equation for this case is:
As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:
Of course, 
.
Now, since the volume of a cone is 
and the ratio 
or 
, the volume becomes:
We proceed to its differentiation:
Then, we compute 
Finally, at h=2:
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