Answer:
equation :water remaining in pool after 30 mins= 0.027X
answer = 67.5 Gallon
Step-by-step explanation:
Given
quantity of water in pool = 2500 gallon
percentage of water lost every 10 mins = 70%
therefore percentage of water remaining in pool = (100- 70)% = 30%
Let the quantity of water in pool be X gallon
% of water remaining in gallon after 10 mins = 30% of X = 0.3X
% of water remaining in gallon after another 10 mins = 30% of water at 10 mins = 30% of 0.3 X = 0.3 * 0.3X = 0.09 X
% of water remaining in gallon after another 30 mins = 30% of water present at 20 minutes = 30% of 0.09 X = 0.3 * 0.09X = 0.027X
Therefore equation of water remaining after 30 mins is = 0.027 X
Substituting value of initial quantity of water in the above equation we get the volume pf water remaining in pool after 30 mins = 0.027 * 2500
= 67.5 gallons
Answer:
2/5
Step-by-step explanation:
in 4/10, both the numerator (4) and denominator (5) are multiples of 2, as 4 = 2 * 2 and 10 = 2 * 5. thus, we can divide both the numerator and denominator by 2 to get
(4/2) / (10/2) = 2/5 as our answer.
Answer:
Hello, maybe their website has a problem? There may be too many requests at a time that servers can't handle. Try again tommorow is what I would recommend.
Revenue = price * number of backpacks
number of backpacks = -2p + 50
p = 9 ; -2(9) + 50 = -18 + 50 = 32
revenue = 9 * 32 = 288
p = 12 ; -2(12) + 50 = -24 + 50 = 26
revenue = 12 * 26 = 312
<u>p = 12.50 ; -2(12.50) + 50 = -25 + 50 = 25</u>
<u>revenue = 12.50 * 25 = 312.50</u> GIVES THE MAXIMUM REVENUE
p = 15 ; -2(15) + 50 = -30 + 50 = 20
revenue = 15 * 20 = 300
