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Vikentia [17]
3 years ago
5

Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecul

es by weak chemical bonds known as _____.
a. Van der Waals interactions
b. ionic bonds
c. hydrogen bonds
d. nonpolar covalent bonds
e. polar covalent bonds
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer: Option (e) is the correct answer.

Explanation:

Atomic number of hydrogen is 1 and atomic number of oxygen is 8 (electronic distribution is 2, 6). When both hydrogen and oxygen atoms chemically combine with each other then sharing of electrons take place between the two atoms.

As a result, a covalent bond is formed. But due to the difference in electronegativity of both hydrogen and oxygen atom there occurs a partial positive and partial negative charge on hydrogen and oxygen atoms.

Hence, water is able to form polar covalent bonds with other polar molecules.

Thus, we can conclude that water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecules by weak chemical bonds known as polar covalent bonds.

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All the following are compounds except. A.water. B.sugar solution. C.aqueous. D.sulphur dioxide
kap26 [50]

Answer:

B.sugar solution

Explanation:

A sugar solution is not a compound.

Rather, the solution is a mixture and an impure substance.

  • A compound is composed of two or more kinds of atoms or elements joined in a definite grouping .
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Is the soup saturated with salt at 20°C? Explain why or why not.
yKpoI14uk [10]
The salt doesn't dissolve at that temperature. heating aids in dissolving
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2 years ago
What is the sum of the atomic numbers of each element present in the reactants of the given formula?
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7 0
3 years ago
Xg of U and 3.795 g of O combine to form 20.00 g of
Deffense [45]

The percent composition of Uranium in U308 = C. 81.03%

<h3>Further explanation</h3>

Given

X g of U

3.795 g of O

20.00 g of  U308

Required

The percent composition of Uranium

Solution

mass of Uranium in U308 :

= mass of U308 - mass of O

= 20 g - 3.795 g

= 16.205 g

The percent composition :

\tt \%U=\dfrac{mass~U}{mass~U308}\times 100\%

%U = (mass U/mass U308) x 100%

%U= (16.205/20) x 100%

%U = 81.025≈81.03

8 0
3 years ago
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