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eimsori [14]
3 years ago
8

The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i

n this solution?
Chemistry
1 answer:
german3 years ago
5 0
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
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Answer:

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Explanation:

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The heat absorbed by the calorimeter can be calculated with the following expression.

Qcal = C × ΔT

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Qcomb = - Qcal

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The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

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3 years ago
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Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

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Formula used to calculate average atomic mass follows:

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As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

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Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

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3 years ago
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Answer:

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Explanation:

self explanatory

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3 years ago
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