Question

A car takes off from rest takes of from rest and covers a distance of 80m on a straight road in 10s.Calculate the magnitude of its acceleration.​

Answer 1

• Initial velocity (u) = 0 m/s [the car was at rest]
• Distance (s) = 80 m
• Time (t) = 10 s
• Let the magnitude of acceleration be a.
• By using the equation of motion, $s = ut + \frac{1}{2} a {t}^{2}$we get,$80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6$

Answer:

The magnitude of its acceleration is 1.6 m/s^2.

Hope you could get an idea from here.

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