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lana [24]
3 years ago
7

Sam is walking through the park. He hears a police car siren moving on the street coming toward him. What happens to the siren s

ound as it approaches and then passes Sam?
a. As the siren approaches Sam, the frequency of sound waves from the siren increase. As the police car continues past Sam, the sound waves decrease in frequency.
b. As the police car approaches Sam, sound waves from the siren remain constant. As the car continues past Sam, the sound waves decrease in frequency.
c. As the police car approaches Sam, the frequency of sound waves from the siren decrease. As the car continues past Sam, the sound waves increase in frequency.
d. As the police car approaches Sam, the frequency of the sounds waves from the siren increases and continues to increase as the car passes and moves away from Sam.
Physics
1 answer:
LiRa [457]3 years ago
5 0
The answer is a.

This is called the Doppler Effect. As a source of sound approaches a stationary object, the frequency observed by the object increases, and as the source of sound passes the stationary object, the frequency decreases.
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borishaifa [10]

Answer:

B

Explanation:

Potential difference has a SI Unit of Volt and its symbol is <em>V</em>. Hence answer is <u>B</u>.

A is wrong as it has the unit Joule <em>(J)</em> which is the SI unit for energy.

C is wrong as it has the unit Newton <em>(N)</em> which is the SI unit for force.

D is wrong as it has the unit Coulomb <em>(C)</em> which is the SI unit of charge.

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3 years ago
Roller coasters accelerates from initial speed of 6.0 M/S2 final speed of 70 M/S over four seconds. What is the acceleration?
choli [55]

Answer:

a=16\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

The formula to calculate the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The roller coaster moves from vo=6 m/s to vf=70 m/s in t=4 seconds. To calculate the acceleration, solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{70-6}{4}=\frac{64}{4}

\boxed{a=16\ m/s^2}

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ycow [4]
I believe that the answer to this would be B




Hope this helped
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attashe74 [19]

Answer:

b the answer is b

Explanation:

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