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lana [24]
3 years ago
7

Sam is walking through the park. He hears a police car siren moving on the street coming toward him. What happens to the siren s

ound as it approaches and then passes Sam?
a. As the siren approaches Sam, the frequency of sound waves from the siren increase. As the police car continues past Sam, the sound waves decrease in frequency.
b. As the police car approaches Sam, sound waves from the siren remain constant. As the car continues past Sam, the sound waves decrease in frequency.
c. As the police car approaches Sam, the frequency of sound waves from the siren decrease. As the car continues past Sam, the sound waves increase in frequency.
d. As the police car approaches Sam, the frequency of the sounds waves from the siren increases and continues to increase as the car passes and moves away from Sam.
Physics
1 answer:
LiRa [457]3 years ago
5 0
The answer is a.

This is called the Doppler Effect. As a source of sound approaches a stationary object, the frequency observed by the object increases, and as the source of sound passes the stationary object, the frequency decreases.
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Suppose the battery in a clock wears out after moving thousand coulombs of charge through the clock at a rate of 0.5 Ma how long
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Answer:

Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

answer :

a) 231.48 days

b) n = 3.125 * 10^15

Explanation:

Battery moved 10,000 coulombs

current rate = 0.5 mA

<u>A) Determine how long the clock run on the battery. use the relation below</u>

q = i * t ----- ( 1 )

q = charge , i = current , t = time

10000 = 0.5 * 10^-3 * t

hence  t = 2 * 10^7 secs

hence the time = 231.48  days

<u>B) Determine how many electrons per second flowed </u>

q = n*e ------ ( 2 )

n = number of electrons

e = 1.6 * 10^-19

q = 0.5 * 10^-3 coulomb ( charge flowing per electron )

back to equation 2

n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )

hence : n = 3.125 * 10^15

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How to find acceleration?
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A. alkali metals

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Answer:

ΔV=0.484mV

Explanation:

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