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Korvikt [17]
2 years ago
12

A scientist studies the growth of plants in a laboratory. Which experimental procedure would provide evidence that

Chemistry
1 answer:
dusya [7]2 years ago
7 0

The experimental procedure would provide evidence that plants need

nitrogen to grow is by

  • Identical plants are placed in two air-tight containers with sufficient exposure to sunlight.
  • One container has nitrogen gas, and the other has room air. The scientist measures plant growth

It is necessary to use identical plants during the experiment as plants have

different rates of nitrogen absorption from the soil. It should also be done in

air-tight containers called terrariums to prevent loss or contamination of the

gases with other elements/compounds.

The identical plants containing nitrogen and room air should both be

measured for the growth difference between them.

Read more on brainly.com/question/972291

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Oleophilic materials would not be used for ?
Elis [28]

Answer:

An oleophilic material is an entity which exhibits a higher affinity for oil than other solvents. The non-polar nature and ability to form cluster-like structures called micelles are the characteristic properties of oleophilic materials.

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6 0
4 years ago
Which nuclear emission is negatively charged?
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6 0
3 years ago
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Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride.Hydrochloric acids is an extremely acidic,clear
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Hydrochloric acid is a strong acid with a distinct pungent smell and it is highly reactive while Sodium hydroxide is a strong base and it is fully Ionic

6 0
3 years ago
Mg(OH)2+HCl=MgCl2+H2O
attashe74 [19]
Left side:
Mg= 1
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Right side:
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5 0
3 years ago
To determine the concentration of 20.00 mL of an unknown solution of a monoprotic acid, it is titrated with 0.1093 M sodium hydr
Elanso [62]

Answer:

d) 0.1202 M

Explanation:

Let's consider the neutralization reaction between NaOH and a generic monoprotic acid.

NaOH + HA → NaA + H₂O

The used volume of NaOH is 41.63 mL - 19.63 mL = 22.00 mL. The moles of NaOH are:

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The molar ratio of NaOH to HA is 1:1. The moles of HA that reacted are 2.405 × 10⁻³ moles.

The molar concentration of HA is:

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