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frosja888 [35]
4 years ago
12

A student constructs an electrochemical cell. A diagram of the operating cell and the unbalanced ionic equation representing the

reaction occurring in the cell are shown below. The blue color of the solution in the copper half-cell indicates the presence of Cu2+ ions. The student observes that the blue color becomes less intense as the cell operates.
Identify the type of electrochemical cell represented by the diagram.
Chemistry
1 answer:
Dominik [7]4 years ago
8 0

Answer:

A voltaic cell

Explanation:

A voltaic cell is a device which converts chemical energy to electrical energy. The chemical reactions that take place inside the cell causes electrons to flow from anode to cathode hence, electricity is produced. A simple voltaic cell is made by placing two different metals in contact with an electrolyte separated by a salt bridge. The cathode is the negative electrode while the anode is the positive electrode. It is also called a galvanic cell.

In a voltaic cell having a copper/copper solution half cell, reduction occurs at the cathode. Hence, at the cathode copper II ions accept two electrons and become reduced to ordinary metallic copper. This causes the blue colour of the solution to become discharged (fade) as the cell continues to function.

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Aspirin (acetylsalicylic acid, C9H8O4) is a weak monoprotic acid. To determine its acid-dissociation constant, a student dissolv
BabaBlast [244]

Answer:

The Ka is 3.74 *10^-4

Explanation:

Step 1: Data given

Mass of aspirin = 2.00 grams

Volume of water = 0.600 L

pH of solution = 2.61

Molar mass of acetylsalicylic acid = 180 g/mol

Step 2: The balanced equation

C9H8O4 + H2O ⇆ H3O+ + C9H7O4-

Step 3: Calculate moles acetylsalicylic acid

Moles acetylsalicylic acid = mass / molar mass

Moles acetylsalicylic acid = 2.00 grams / 180 g/mol

Moles acetylsalicylic acid = 0.0111 moles

Step 4: The initial concentration

[C9H8O4] = 0.0111 moles / 0.600 L = 0.0185 M

[H3O+] = 0M

[C9H8O4-] = 0M

Step 5: The concentration at the equilibrium

[C9H8O4] =0.0185 - X M

[H3O+] = XM

[C9H8O4-] = XM

Step 6: Calculate Ka

Ka = [H3O+][C9H7O4-] / [C9H8O4]

Ka = x² / (0.0185 - x)

pH = 2.61;  [H3O+] = 10^-pH = 10^-2.61 = 0.00245 = x

Ka = (0.00245)² / (0.0185 - 0.00245) = 3.74 * 10^-4

The Ka is 3.74 *10^-4

8 0
3 years ago
Answer all 3 parts correctly and I will give you a Brainliest, 5-star rating, and thanks on question and profile
pishuonlain [190]

Answer:

Mark me as brain list plz for fun

Explanation:

The picture is blurry

4 0
3 years ago
Read 2 more answers
Question 4 (2 points)<br> CuO(s) + H2(g)<br> Cu(s) +<br> H2O(1)<br> Balance the equation
CaHeK987 [17]

Answer:

CuO(s) + H₂(g) --> Cu(s) + H₂O(l)

Explanation:

It is already balanced. You can see that the values of the elements of the reactants are equal to the values of the elements of the products.

7 0
3 years ago
Perform the following operation
Paul [167]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:2.8 × {10}^{-5}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \dfrac{2.36 \times 10 {}^{ - 2} }{8.4  \times {10}^{2} }

\qquad \tt \rightarrow \:  \dfrac{2.36  }{8.4   } \times  \cfrac{10 {}^{ - 2} }{10 {}^{2} }

\qquad \tt \rightarrow \:  0.28 \times 10 {}^{ - 2 - 2}

\qquad \tt \rightarrow \:  0.28  \times 10 {}^{  - 4}

\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
Please help
lora16 [44]
Find the molar mass of CH3 and divide that by 45.0. That should give a whole number and then mult that whole number by CH3 to find molecular formula to get like ( incorrect ex: C2H6) which is mult by 2
6 0
3 years ago
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