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frosja888 [35]
3 years ago
12

A student constructs an electrochemical cell. A diagram of the operating cell and the unbalanced ionic equation representing the

reaction occurring in the cell are shown below. The blue color of the solution in the copper half-cell indicates the presence of Cu2+ ions. The student observes that the blue color becomes less intense as the cell operates.
Identify the type of electrochemical cell represented by the diagram.
Chemistry
1 answer:
Dominik [7]3 years ago
8 0

Answer:

A voltaic cell

Explanation:

A voltaic cell is a device which converts chemical energy to electrical energy. The chemical reactions that take place inside the cell causes electrons to flow from anode to cathode hence, electricity is produced. A simple voltaic cell is made by placing two different metals in contact with an electrolyte separated by a salt bridge. The cathode is the negative electrode while the anode is the positive electrode. It is also called a galvanic cell.

In a voltaic cell having a copper/copper solution half cell, reduction occurs at the cathode. Hence, at the cathode copper II ions accept two electrons and become reduced to ordinary metallic copper. This causes the blue colour of the solution to become discharged (fade) as the cell continues to function.

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7 0
2 years ago
Why does the chemical reaction seen here obey the law of conservation of matter?
ss7ja [257]

Why does the chemical reaction seen here obey the law of conservation of matter?

<u><em>Answer:</em></u>

  • Because there are the same number of atoms of each element shown on both sides

<u><em>Explanation</em></u>

  • As in chemical reactions, atoms bonds are break and new bonds are formed. As new substance are formed but overall they have same elements, no new elements come from outside or go to outside. In other words , rearrangement of atoms take place but number of atoms remained same.

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  • As in above reaction there are the same number of atoms of each element shown on both sides .
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3 years ago
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2 years ago
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Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.
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Answer is: the ratio of the effusion rate is 1.59 : 1.

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rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.  

2) rate of effusion of chlorine = 1/√M(Cl₂).  

rate of effusion of chlorine = 1/√70.9.  

rate of effusion of chlorine = 0.119.  

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= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

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