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sveta [45]
3 years ago
5

BRAINLIESTTT ASAP!!! PLEASE HELP ME :)

Chemistry
2 answers:
umka21 [38]3 years ago
6 0

Hey Geny :)

I’m pretty sure the answer is B

Hope this helps you

-AaronWiseIsBae

Katarina [22]3 years ago
5 0

Answer:

Metals lose their valence electrons and form positive ions.

Explanation:

TOOK THE TEST AND GOT IT RIGHT

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What is the molarity of 0.65 mol NaF dissolved in a total volume of 0.50 liters?
arsen [322]

Answer:

1.3 M

Explanation:

The question asks to calculate the molarity of a solution.

We have to use the following equitation:

Molarity = # moles / 1 lt of solution

In this case we have a solution composed of 0.65 mol of NaF diluted in a total volume of 0.5 lt. We will have to do the following cross multiplication solving for x:

0.65 mol NaF / 0.5 lt = x mol NaF/ 1 lt

x = 1.3 mol NaF / 1 lt = 1.3 M

5 0
3 years ago
When the equation H202 + H2O + O2 is completely balanced, the SUM of all the coefficients will be
Leviafan [203]
Answer: 1. 5
2H202 -> 2H2O + O2 ; 2 + 2 +1 = 5
7 0
2 years ago
If you have a 1500 g aluminum pot, how much heat energy is needed to raise its temperature by 100°C?
Nataly [62]

The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.

The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

Explanation:

The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.

So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).

Then, the heat energy required to raise the temperature will be

q = m*c*del T = 1500 * 0.900 * 100 = 135000 = 135 kJ

Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.

Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100  °C.

Then, the heat energy required to raise its temperature will be

q = m*c*del T = 1500 * 0.385 * 100 = 57750 = 57.75 kJ

And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.

So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

8 0
3 years ago
11. What is the concentration (in M) of an ammonia (NH3) solution if 12.23 grams of ammonia are
photoshop1234 [79]

Answer:  1.284M NH3

Explanation:  (12.23 grams)/(17.0 gramms/mole) = 0.7191 moles

Dissolved in 560.0 ml (=0.5600L)

(0.7191 moles)/(0.560L) = 1.284M  (4 sig figs)

5 0
2 years ago
Which element from the periodic table has four valence electrons
Ivahew [28]

carbon has 4 valence electrons

6 0
2 years ago
Read 2 more answers
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