<span>The product of Craig's savings is 4 and 76. Use the variable g to represent
</span>Use the variable c to represent Craig's savings.<span>
g = 4*76 = 304</span>
a = 1, b =14 and y-coordinate is 6 when x = 0.
Solution:
Let us first write the equation of a line.
Take the points are (2, 2) and (6, 10).
Slope of the line:



m = 2
Point-slope formula:

y - 10 = 2(x - 2)
y - 10 = 2x - 4
Add 10 on both sides,we get
y = 2x + 6
Equation of a line is y = 2x + 6.
To find (a, 8), substitute x = a and y = 8 in the equation,
8 = 2a + 6
Subtract 6 from both sides, we get
2 = 2a
a = 1
To find (4, b), substitute x = 4 and y = b in the equation,
b = 2(4) + 6
b = 8 + 6
b = 14
Substitute x = o in the equation.
y = 2(0) + 6
y = 6
The y-coordinate is 6 when x = 0.
Answer:
x=4.5 and y= -6
Step-by-step explanation:
2x+5y= -21
-2x+3y= -27
add the two equations: 8y= -48
y=-48/8= -6
sub for y in 2x+5y= -21
2x + 5(-6)=-21, 2x-30= -21
2x= -21+30= 9
x= 9/2=4.5
Answer:
D) ![\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For matrix ![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
the inverse matrix is the transpose of the cofactor matrix, divided by the determinant: ![\dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bad-bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dd%26-b%5C%5C-c%26a%5Cend%7Barray%7D%5Cright%5D)
Your inverse matrix is: ![\dfrac{1}{2(-3)-(1)(2)}\left[\begin{array}{cc}-3&-1\\-2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%28-3%29-%281%29%282%29%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-1%5C%5C-2%262%5Cend%7Barray%7D%5Cright%5D)
so the solution is ...
![\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{cc}\frac{3}{8}&\frac{1}{8}\\\frac{1}{4}&-\frac{1}{4}\end{array}\right] \cdot\left[\begin{array}{c}2\\4\end{array}\right] =\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right] \qquad\text{matches selection D}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B8%7D%26%5Cfrac%7B1%7D%7B8%7D%5C%5C%5Cfrac%7B1%7D%7B4%7D%26-%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%5Ctext%7Bmatches%20selection%20D%7D)