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DaniilM [7]
2 years ago
8

What is the gpe of a 200g ball that is 10m off the ground​

Physics
1 answer:
rodikova [14]2 years ago
8 0

Answer:

gpe gained = 20J

Explanation:

gpe = mass * gravity * height

gpe = (200/1000) kg * 10 * 10

gpe  = 20J

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A car of mass 1000 kg is travelling at 10 m/s. What is its kinetic energy?
Marysya12 [62]

Answer:

50,000

Explanation:

kinetic energy=1\2×mv^2

=1\2×1000kg×10×10

=50000

6 0
3 years ago
When two objects of different masses, different temperatures, and different sizes are placed in thermal contact, energy will alw
denpristay [2]

Answer:

a) from the hotter object to the cooler object

Explanation:

temperature moves by conduction,  which is associated with the movement of  atoms or molecules and the always move from hight temperatures to lower temperatures to attain thermal equilinrium of the system.

so when two objects are placed together and have different temperatures then the system is not in thermal equilibrium and to attain it, temperature can only move to coller object and not from the coller object according to thermodynamics.

6 0
3 years ago
A tuning fork with a frequency of 335 Hz and a tuning fork of unknown frequency produce beats with a frequency of 5.3 when struc
Ganezh [65]

Answer:

Explanation:

Unknown fork frequency is either

335 + 5.3 = 340.3 Hz

or

335 - 5.3 = 329.7 Hz

After we modify the known fork, the unknown fork frequency equation becomes either

(335 - x) + 8 = 340.3

(335 - x)  = 332.3

x = 2.7 Hz

or

(335 - x) + 8 = 329.7

(335 - x) = 321.7

x = 13.3 Hz

IF the unknown fork frequency was 340.3 Hz,

THEN the 335 Hz fork was detuned to 335 - 2.7 = 332.3 Hz

IF the unknown fork frequency was 329.7 Hz,

THEN the 335 Hz fork was detuned to 335 - 13.3 = 321.7 Hz

3 0
3 years ago
The process of combining two small nuclei into one nucleus of larger mass is called _____.
fiasKO [112]
The process of splitting one large nucleus into
smaller ones is nuclear fission.

The process of combining two small nuclei into
one larger one is nuclear fusion.
3 0
3 years ago
Read 2 more answers
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Tems11 [23]

Answer:

5.4 ms⁻¹

Explanation:

Here we have to use conservation of energy. Initially when the stick is held vertical, its center of mass is at some height above the ground, hence the stick has some gravitational potential energy. As the stick is allowed to fall, its rotates about one. gravitational potential energy of the stick gets converted into rotational kinetic energy.

L = length of the meter stick = 1 m

m = mass of the meter stick

w = angular speed of the meter stick as it hits the floor

v = speed of the other end of the stick

we know that, linear speed and angular speed are related as

v = r w\\w = \frac{v}{r}

h = height of center of mass of meter stick above the floor = \frac{L}{2} = \frac{1}{2} = 0.5 m

I = Moment of inertia of the stick about one end

For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

Rotational kinetic energy of the stick = gravitational potential energy

(0.5) I w^{2} = mgh\\(0.5)(\frac{mL^{2} }{3}) (\frac{v}{L} )^{2} = mgh\\(0.5)(\frac{v^{2} }{3}) = gh\\(0.5)(\frac{v^{2} }{3}) = (9.8)(0.5)\\v = 5.4 ms^{-1}

7 0
3 years ago
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