Answer: ![1.50075*10^{-10}\ N](https://tex.z-dn.net/?f=1.50075%2A10%5E%7B-10%7D%5C%20N)
Explanation:
For this exercise we need to use the Gravitational Force Formula. This is:
![F_g=G(\frac{m_1*m_2}{r^2})](https://tex.z-dn.net/?f=F_g%3DG%28%5Cfrac%7Bm_1%2Am_2%7D%7Br%5E2%7D%29)
Where
is the gravitational force between two objects,
is the gravitational constant (
) and
is the distance between the objects.
We know that:
![m_1=6.0\ kg\\\\m_2=6.0\ kg\\\\r=4.0\ m](https://tex.z-dn.net/?f=m_1%3D6.0%5C%20kg%5C%5C%5C%5Cm_2%3D6.0%5C%20kg%5C%5C%5C%5Cr%3D4.0%5C%20m)
Therefore, in order to calculate the magnitude of the gravitational force between the two masses, we must substitute these values into the formula.
Then we get:
![F_g=(G=6.67*10^{-11}\ \frac{Nm^2}{kg^2})(\frac{(6.0\ kg)(6.0\ kg)}{(4.0\ m)^2})\\\\F_g=1.50075*10^{-10}\ N](https://tex.z-dn.net/?f=F_g%3D%28G%3D6.67%2A10%5E%7B-11%7D%5C%20%5Cfrac%7BNm%5E2%7D%7Bkg%5E2%7D%29%28%5Cfrac%7B%286.0%5C%20kg%29%286.0%5C%20kg%29%7D%7B%284.0%5C%20m%29%5E2%7D%29%5C%5C%5C%5CF_g%3D1.50075%2A10%5E%7B-10%7D%5C%20N)
Answer:
Explanation:
Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag. If forces are in opposite directions, like lift and weight, then you subtract them
Answer:
![a=0.13m/s^2](https://tex.z-dn.net/?f=a%3D0.13m%2Fs%5E2)
Explanation:
From the question we are told that
Mass of first team man ![m_1=64kg](https://tex.z-dn.net/?f=m_1%3D64kg)
Force of man first team man ![F_1=1350](https://tex.z-dn.net/?f=F_1%3D1350)
Mass of second team man ![m_2=69kg](https://tex.z-dn.net/?f=m_2%3D69kg)
Force of man second team man ![F_2=1367N](https://tex.z-dn.net/?f=F_2%3D1367N)
Generally the equation for net force F_n is mathematically given by
![F_n=9(m_1+m_2)a](https://tex.z-dn.net/?f=F_n%3D9%28m_1%2Bm_2%29a)
![9(m_1+m_2)a=9(f_2-f_1)](https://tex.z-dn.net/?f=9%28m_1%2Bm_2%29a%3D9%28f_2-f_1%29)
![9(64+69)a=9(1367-1350)](https://tex.z-dn.net/?f=9%2864%2B69%29a%3D9%281367-1350%29)
![a=\frac{9(1367-1350)}{9(64+69)}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B9%281367-1350%29%7D%7B9%2864%2B69%29%7D)
![a=0.127819m/s^2](https://tex.z-dn.net/?f=a%3D0.127819m%2Fs%5E2)
Therefore the acceleration is given by
![a=0.13m/s^2](https://tex.z-dn.net/?f=a%3D0.13m%2Fs%5E2)