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koban [17]
2 years ago
6

The process of combining two small nuclei into one nucleus of larger mass is called _____.

Physics
2 answers:
ladessa [460]2 years ago
6 0

The correct answer to the question is Fusion i.e the process of combining two small nuclei into one nucleus of larger mass is called fusion.

EXPLANATION:

Before answering this question, first we have to understand nuclear fission and nuclear fusion.

Nuclear fission is the thermo nuclear process in which a heavy unstable nucleus will split into two light stable nuclei with the release of energy.

For instance, the splitting of Uranium-235 to Krypton-92 and Barium-141.

Nuclear fusion is just the opposite process of nuclear fission. It is the thermo nuclear process in which two light unstable nuclei will combine with each other at  a high temperature equal to the temperature of sun to form a large stable nuclei with the release of energy.

For instance, we may take hydrogen bomb i.e the energy formation in stars. Here, four hydrogen nuclei will combine with each other form a helium nuclei with the release of huge amount of energy.

Hence, the correct answer to the question is nuclear fusion.

fiasKO [112]2 years ago
3 0
The process of splitting one large nucleus into
smaller ones is nuclear fission.

The process of combining two small nuclei into
one larger one is nuclear fusion.
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An object with a charge of -3.2 uC and a mass of 1.0×10^(-2) kg experiences an upward electric force, due to a uniform electric
USPshnik [31]

Answer:

The magnitude of the acceleration is equal to 19.6m/s² and the acceleration is directed upwards though the magnitude of the charge has doubled. This is because the electric force is directed upwards and from newton's second law of motion the charge will have acceleration in the same direction as the electric force on the charge.

Explanation:

The detailed solution can be found in the attachment below.

Thank you for reading and I hope this is helpful to you.

6 0
3 years ago
A 2320 pound roller coaster starts from rest and is launched such that it creates a 110 ft high hill with a speed of 65 mph. The
Sergeu [11.5K]

Answer: E = 941738.537J

Explanation:

to begin,

given that the mass = 2320 pound = 1052.334 kg

Δh = 110 ft = 33.528 m

given that  distance (d) = 1283 ft = 391.058 m

also the speed (v) is 65 mph = 29.058 m/s

force (F) = 87 pounds = 386.995 N

from our knowledge in work energy theory;

E = Fd + 1/2mv² + mgh

E = (386.995 × 391.058) + (1/2×1052.334×29.058²) + (1052.334×9.81×33.528)

E = 151337.491 + 444278.2 + 346122.84

E = 941738.537J

i hope this helps, cheers.

3 0
3 years ago
Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is mo
kkurt [141]

Answer:increased

Explanation:

It is given that elevator speed is increasing while moving upward i.e.its acceleration is increasing .

This causes the apparent to be increased if measured using weighing machine.

considering upward direction to be positive

N-mg=ma

N=m(g+a)

where N=Normal reaction=Apparent weight

a=acceleration of Elevator

thus you feel as if your weight is increased.

6 0
3 years ago
Teens realize that things may be “shades of gray” after they enter Piaget’s
expeople1 [14]
Teens realize that things may be “shades of gray” after they enter Piaget’s formal operational stage. The Piaget's approach for Adolescent, also referred to asFormal operational stage is the stage in which adolescents develop their ability to think about abstract concepts, they become more argumentative and <span>indecisive.</span>
5 0
3 years ago
Read 2 more answers
nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluorid
loris [4]

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

For F-F

159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

3 0
3 years ago
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