A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1).
1 answer:
The reading on the scale is equal to the weight of the student which is 646.8 N.
The given parameters;
- <em>mass of the student, m = 66 kg</em>
The reading on the scale is determined by applying Newton's second law of motion as follows;
<em>The student is at rest and not accelerating, a =0</em>
Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.
The complete question is below:
A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?
Learn more about Newton's second law here: brainly.com/question/3999427
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To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by
Where,
T = Tension
Linear density
Our data are given by
Tension , T = 70 N
Linear density ,
Amplitude , A = 7 cm = 0.07 m
Period , t = 0.35 s
Replacing our values,
Speed can also be expressed as
Re-arrange to find \lambda
Where,
f = Frequency,
Which is also described in function of the Period as,
Therefore replacing to find
Therefore the wavelength of the waves created in the string is 3.49m
Answer:
a) 5.63 atm
Explanation:
We can use combined gas law
<em>The combined gas law</em> combines the three gas laws:
- Boyle's Law, (P₁V₁ =P₂V₂)
- Charles' Law (V₁/T₁ =V₂/T₂)
- Gay-Lussac's Law. (P₁/T₁ =P₂/T₂)
It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.
P₁V₁/T₁ =P₂V₂/T₂
where P = Pressure, T = Absolute temperature, V = Volume occupied
The volume of the system remains constant,
So, P₁/T₁ =P₂/T₂
a)