Simple!

Since we can observe that they all have the same denominators (bottom part) we can just observe the numerator (top part)

6 is indeed greater than 5, yes? So we can safely say that

6/8 > 5/8

Now the for the second part.

6 is smaller than 7, yes? So we can make the observation that

6/8 < 7/8

Hope that makes sense! (Be sure to thank me, plz)

P.S. If you want an example of unlike denominators, let me know.

7 0

3 years ago

Consider the integral 8 (x2+1) dx 0 (a) Estimate the area under the curve using a left-hand sum with n = 4. 250 Is this sum an o

Leya [2.2K]

Answer:

(a) 120 square units (underestimate)

(b) 248 square units

Step-by-step explanation:

(a) left sum

See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.

left sum = 2(1 + 5 + 17 + 37) = 2(60) = 120 . . . . square units

(b) right sum

The right sum is the sum of the last 4 table values for f(x), each multiplied by 2 (the width of the rectangle). This sum is ...

right sum = 2(5 +17 + 37 +65) = 2(124) = 248 . . . . square units

3 0

3 years ago

I really need this it's a test

faltersainse [42]

Move all terms not containing x to the right side of the equation

x=9

8 0

3 years ago