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2 years ago

What is the value of x in the equation −x = 4 − 3x + 6? 5 10 −5 −10

Mathematics

2 answers:

Vanyuwa [196]2 years ago

7 0

The answer is x=6
Hope this helps

erma4kov [3.2K]2 years ago

3 0

The answer is 5. Group the like terms add the numbers then add 3x to both sides simplify and divide both sides and simplify and you get 5.

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What is a polynomial Can anyone answer with the definition of Quadrilateral

pashok25 [27]

Polynomial is an expression of more than two algebraic terms.

<h3>Definition of quadrilateral:</h3>

A quadrilateral is a four-sided polygon with four edges (sides) and four corners in geometry (vertices).
The name comes from the Latin words quadri, which means "four," and latus, which means "side."
In comparison to other polygons, it is also known as a tetragon, derived from the Greek "tetra" meaning "four" and "gon" meaning "corner" or "angle"
In the same way as other polygons (e.g. pentagon). While "gon" means "angle," it's also known as a quadrangle or 4-angle.

more info: https://brainly.in/question/4869171

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4 0

1 year ago

Read 2 more answers

A tire maker produces 20000 tires to be shipped. they inspect 200 of the tires and find that 16 or defective. how many tires of

Xelga [282]

$\frac{16}{200} = \frac{2}{25}$
is the proportion of tires that are defective so
$\frac{2}{25} \times 20000 = 1600$
so we would expect around 1600 tires to be defective

4 0

2 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

2 years ago

Triangle P R Q is shown. Angle R P Q is 39 degrees. The length of P R is 6, the length of R Q is p, and the length of P Q is 8.

KATRIN_1 [288]

According to law of cosines the length of RQ can be written as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.

A length of the triangle can be written as according to law of cosines if sides are given and one angle is $a^{2} =b^{2} +c^{2} -2bccos(A)$

We have to just put the values in the above equation.

as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.

Hence the side can be written as according to law of cosines if the angle is 39 degrees is as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

Learn more about trigonometric functions at brainly.com/question/24349828

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7 0

1 year ago

There are five blue colored balls, 3 red colored balls, and two black colored balls in a container. Another container has one pi

galina1969 [7]

Answer:

Option 3

Step-by-step explanation: I think it is option 3

6 0

2 years ago