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Elan Coil [88]
3 years ago
9

Find the quadratic equation whose roots are 3+- i / 2

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0
(x - root#1) times (x - root#2) = 0 . . . . . This is how to BUILD the quadratic equation.


All the rest is just multiplying out that first line:

(x- (3+i/2)) times (x - (3-i/2)) = 0

x² -x(3-i/2) -x(3+i/2) + (3+i/2)(3-i/2) = 0

x² -3x + ix/2 -3x - ix/2 + 9 -3i/2 + 3i/2 = 0

<u>x² -6x +9 = 0</u>  There it is.  That's your quadratic equation.
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10 = 7 - m*<br> It says solve &amp; check solution. Can someone help asap
Stels [109]

Answer:

see explanation

Step-by-step explanation:

Given

10 = 7 - m ( subtract 3 from both sides )

3 = - m ( multiply both sides by - 1 )

- 3 = m , or

m = - 3

As a check

Substitute m = - 3 into the right side of the equation and if equal to the left side then it is the solution

7 - m = 7 - (- 3) = 7 + 3 = 10 = left side

Thus m = - 3 is the solution to the equation

7 0
3 years ago
Find the equation of the line that passes through the point (3,14) and is parallel to y=2/3x -6
Ugo [173]
Y=mx+b
m=slope

paralell ines have same slope
y=2/3x-6
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the equation of aline that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
(3,14) and slope is 2/3
y-14=2/3(x-3)
y-14=2/3x-2
y=2/3x+12
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3 years ago
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MArishka [77]

Answer:

1 option is correct

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Angle AOB and DOC is vertically opposite angle

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