Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure

![P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}](https://tex.z-dn.net/?f=P_%7Br%7D%3D%5Cdfrac%7BP%7D%7BAc%7D%3C%2Fp%3E%3Cp%3EPut%20the%20value%20into%20the%20formula%3C%2Fp%3E%3Cp%3E%5Btex%5DP_%7Br%7D%3D%5Cdfrac%7B26.0%5Ctimes10%5E%7B6%7D%7D%7B%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-2%7D%29%5E2%5Ctimes3%5Ctimes10%5E%7B8%7D%7D)

We need to calculate the force
Using formula of force


Put the value into the formula


We need to calculate the acceleration
Using formula of force

Put the value into the formula




(a). We need to calculate speed of the block
Using equation of motion

Put the value into the formula


(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No
expressing adverse or disapproving comments or judgments.
The relation between temperature and pressure is called the "equation of state of the gas". or "Hydrostatic equilibrium in ordinary star". Take for example a balloon, it will have a larger spherical shape, if the pressure inside exerted by the gas on a wall of a balloon balance the inward force exerted by the outside atmospheric pressure. In a dying star which is being compressed by gravity, the gas is being squeezed so the molecules is moving rapidly, resulting to a very high temperature, and this provide a balance that counteract or balances the compressive force of gravity. The very high temperature inside the star is needed to balance the force of gravity, and it is provide by "nuclear fusion energy" or else the star would collapse under the force of gravity. Depending on the size or mass of the star, it will either become, a "neutron star" or a "black hole".
Answer:
5.3 cm
Explanation:
This question is an illustration of real and apparent distance.
From the question, we have the following given parameters
Real Distance, R = 8.0cm
Refractive Index, μ = 1.5
Required
Determine the apparent distance (A)
The relationship between R, A and μ is:
μ = R/A
i.e.
Refractive Index = Real Distance ÷ Apparent Distance
Substitute values in the above formula
1.5 = 8/A
Multiply both sides by A
1.5 * A = A * 8/A
1.5A = 8
Divide both side by 1.5
1.5A/1.5 = 8/1.5
A = 8/1.5
A = 5.3cm
Hence, the letters would appear at a distance of 5.3cm
Answer:
The answer is B) Double slit