There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
11+i
that’s the answer hope it helps:)
<em>Answer:</em>
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<em>Step-by-step explanation:</em>
<em>Khan academy huh?</em>
- <em>put the numbers in order from least to greatest.</em>
- <em>find the median</em>
- <em>find the difference between the median and all of the other numbers.</em>
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<em>P.S. If you were looking for somebody to tell you the answer don't hold your breath.</em>
The answer should be (7x+1)(7x-1)
