Question

A 0.095 kg tennis ball is traveling to the right at 40 m/s when it bounces of a wall and travels in the opposite direction it came from. The bounced leaving the wall with a speed of 30 m/s. What is (Δp) the change in momentum of the ball? kg·m/s

Answer 1

given that

mass of ball = 0.095 kg

initial velocity of ball towards the wall = 40 m/s

final velocity of the ball after it rebound = 30 m/s

now change in momentum is given as

$\Delta P = m(v_f - v_i)$

$\Delta P = 0.095(30 - (-40))$

$\Delta P = 6.65 kg m/s$

So change in momentum will be 6.65 kg m/s