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notsponge [240]
3 years ago
6

Johannes Kepler used math to show that the planets move in perfect circles around the sun.

Physics
2 answers:
romanna [79]3 years ago
6 0
Ture have a nice dya :)
svet-max [94.6K]3 years ago
4 0
Kepler actually showed that the planets move around the sun in ellipses, not circles. So the answer is false.
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When you look at the light from distant stars you are really looking back in time explain what this means
Leona [35]

Answer: Stars are in space for very long time, much longer than that one night. You are looking back in time because those stars have been there for so long that it’s like looking back in time, to when those stars were there.

Explanation:

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5 0
3 years ago
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What component of fitness should you work on every time you exercise?
Pepsi [2]

Answer:

1.body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardio respiratory endurance.

Explanation:

8 0
3 years ago
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Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
maxonik [38]

Explanation:

It is given that,

Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz

The speed of the sound in air, v = 343 m/s

(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

\lambda_1=\dfrac{343\ m/s}{3820\ Hz}

\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}

\lambda_2=0.43\ m

Hence, this is the required solution.

7 0
3 years ago
Two boxes (m1 = 43.0 kg and m2 = 39.5 kg) are connected by a light string that passes over a light, frictionless pulley. One box
wlad13 [49]
The net force on the system:
F = m₂g - m₁gsin(∅)
F = 39.5 x 9.81 - 43 x 9.81 x sin(30)
F = 176.58 N

Now, we use F = ma to find the acceleration on each mass.
F = m₁a₁
a₁ = 176.58 / 43
a₁ = 4.11 m/s²

F = m₂a₂
a₂ = 176.58 / 39.5
a₂ = 4.47 m/s²
5 0
4 years ago
The area of the tympanic membrane is 100 mm 2 and the area of the oval window is 5 mm 2 . if a sound wave applies 10 n to the ty
Flura [38]
<span>The answer is "0.5N".


According to the question;
P1=P2
so,
F1/A1= F2/A2

P=(F/A)

A1=100mm</span>²
<span>
F1= 10N

A2= 5mm</span>²
<span>
F2= ? 

F2= ((F1 x A2)/A1)
= ((10 x 5) /100)

=50/100

=0.5N</span>
8 0
3 years ago
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