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jolli1 [7]
3 years ago
6

What is the to top-level consumers

Physics
1 answer:
Harrizon [31]3 years ago
3 0

Level 1: Plants and algae make their own food and are called producers. Level 2: Herbivores eat plants and are called primary consumers.

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A boy is trying to roll a bowling ball up a hill, as shown in the image below. If
kherson [118]

The minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s. The correct option is D.

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A boy is trying to roll a bowling ball up a hill. The friction is ignored.  The ball must have to reach the top of the hill with a velocity. The acceleration due to gravity, g = 9.8 m/s²

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

M.E bottom of hill = M.E on top of hill

Kinetic energy + Potential energy = Kinetic energy  + Potential energy

1/2 mu² + 0 =  0 + mgh

At the top of hill, the velocity will become zero. So, final kinetic energy is zero.

Substituting the values, we have

1/2 x u² = 9.8 x 22.5

u = sqrt [2 x9.8 x 22.5 ]

u= 21 m/s

Thus, the minimum initial velocity that the ball must have for it to reach the top of the hill is 21 m/s.

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

4 0
2 years ago
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span o
wariber [46]

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

<h3>What is power?</h3>

In physics, power (P) is the work (W) done over a period of time.

  • Step 1. Calculate the work done by the bodybuilder each time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

  • Step 2. Calculate the work done by the bodybuilder over 10 times.

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

  • Step 3. Calculate the power exerted by the bodybuilder.

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

Learn more about power here: brainly.com/question/911620

#SPJ1

4 0
1 year ago
HELP PLEASE <br> Find the net force necessary for a 15 kg object to accelerate at 20 m/s/s.
tensa zangetsu [6.8K]

Answer:

<h3>The answer is 300 N</h3>

Explanation:

The force acting on an object given the mass and acceleration we use the formula

<h3>force = mass × acceleration</h3>

We have

force = 15 × 20

We have the final answer as

<h3>300 N</h3>

Hope this helps you

3 0
3 years ago
What is a milliliter.
zavuch27 [327]

Answer:

one thousandth of a liter (0.002 pint).

Explanation:

7 0
3 years ago
Read 2 more answers
Large amounts of water that quickly infiltrate soil on a sloped surface can
sergey [27]
A is the correct choice
7 0
3 years ago
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