First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
Soda ash which is also referred to as sodium carbonate with a chemical formula (NaCO3) has the following chemical formula
The melting point of 851 degrees
The molecular weight of 105.98
Its density at 25 degrees is =2.53 g/cm^3
Its specific heat capacity at 25 degrees = 0.249 cal/gm/ 0c
Answer:
25.2°C
Explanation:
Given parameters:
Energy applied to the water = 1000J
Mass of water = 50g
Final temperature = 30°C
Unknown:
Initial temperature = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the energy absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
1000 = 50 x 4.184 x (30 - initial temperature )
1000 = 209.2(30 - initial temperature)
4.78 = 30 - initial temperature
4.78 - 30 = - initial temperature
Initial temperature = 25.2°C
Answer:
The answer is
<h2>20 %</h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula
![P(\%) = \frac{error}{actual \: \: number} \times 100\% \\](https://tex.z-dn.net/?f=P%28%5C%25%29%20%3D%20%20%5Cfrac%7Berror%7D%7Bactual%20%5C%3A%20%20%5C%3A%20number%7D%20%20%5Ctimes%20100%5C%25%20%5C%5C%20)
From the question
actual volume = 35 mg
error = 35 - 28 = 7
The percentage error is
![P(\%) = \frac{7}{35} \times 100 \\ = \frac{1}{5} \times 100 \\ = 20](https://tex.z-dn.net/?f=P%28%5C%25%29%20%3D%20%20%5Cfrac%7B7%7D%7B35%7D%20%20%5Ctimes%20100%20%5C%5C%20%20%3D%20%20%5Cfrac%7B1%7D%7B5%7D%20%20%5Ctimes%20100%20%5C%5C%20%20%3D%20%2020)
We have the final answer as
<h3>20 %</h3>
Hope this helps you
Answer: The heat absorbed by the water is 52.823 J.
Explanation:
Given: Mass of metal = 5.05 g
Specific heat of water = 4.184 ![J/g^{o}C](https://tex.z-dn.net/?f=J%2Fg%5E%7Bo%7DC)
Initial temperature = ![24.8^{o}C](https://tex.z-dn.net/?f=24.8%5E%7Bo%7DC)
Final temperature = ![27.3^{o}C](https://tex.z-dn.net/?f=27.3%5E%7Bo%7DC)
Formula used to calculate heat absorbed is as follows.
![q = m \times C \times (T_{2} - T_{1})](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29)
where,
q = heat
m = mass of substance
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = m \times C \times (T_{2} - T_{1})\\= 5.05 g \times 4.184 J/g^{o}C \times (27.3 - 24.8)^{o}C\\= 52.823 J](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29%5C%5C%3D%205.05%20g%20%5Ctimes%204.184%20J%2Fg%5E%7Bo%7DC%20%5Ctimes%20%2827.3%20-%2024.8%29%5E%7Bo%7DC%5C%5C%3D%2052.823%20J)
Thus, we can conclude that heat absorbed by the water is 52.823 J.