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3 years ago

A mixture of chalk powder and water can be

Chemistry

1 answer:

grin007 [14]3 years ago

4 0

Answer:

<h3>Right answer is: ( a) chalk powder remains suspended in water.</h3>

Explanation:

Filtration is the technique used to separate suspended solute particles from a solution . The chalk powder remains suspended in the solution and can easily be filtered through a filter paper , the chalk powder can be collected on the filter paper and clear solvent is collected as the filtrate.

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What salt is produced in each of the following neutralization reactions?

Pavlova-9 [17]

1. Salt is KNO₃

This is a strong acid - strong base reaction. HNO₃ is the strong acid and KOH is the strong base. 

H⁺ in the HNO₃ and OH⁻ of the KOH pair up and make H₂O(l). 

NO₃⁻ and K⁺ pair up to make KNO₃ salt. 

When writing chemical formulas positive ion comes first and second is negative ion. The charges should be switched. Since positive ion has +1 and negative ion has -1 after the switching off charges the product should be KNO₃.

Balance equation is 
HNO₃(aq) + KOH(aq) → H₂O(l) + KNO₃(aq)

2. Salt is Ca(NO₃)₂

This is a strong acid - strong base reaction. HNO₃ is the strong acid and Ca(OH)₂ is the strong base. 

H⁺ in the HNO₃ and OH⁻ of the Ca(OH)₂ pair up and make H₂O(l). 

Ca²⁺ and NO₃⁻ pair up to make Ca(NO₃)₂ salt. 

Positive ion is Ca²⁺ which has +2 charge and negative ion is NO₃⁻ which has -1 charge. From switching the charges Ca²⁺ gets 1 while NO₃⁻ gets 2. Hence, the salt should be Ca(NO₃)₂.

Balanced equation is
2HNO₃(aq) + Ca(OH)₂(aq) → 2H₂O(l) + Ca(NO₃)₂(aq)

3. Salt is CaCl₂

This is a strong acid - strong base reaction. HCl is the strong acid and Ca(OH)₂ is the strong base. 

H⁺ in the HCl and OH⁻ of the Ca(OH)₂ pair up and make H₂O(l). 

Ca²⁺ and Cl⁻ pair up to make CaCl₂ salt. 

Positive ion is Ca²⁺ which has +2 charge and negative ion is Cl⁻ which has -1 charge. By switching the charges Ca²⁺ gets 1 while NO₃⁻ gets 2. Hence, the salt should be CaCl₂.

Balance equation is
2HCl(aq) + Ca(OH)₂(aq) → 2H₂O(l) + CaCl₂(aq)

4. Salt is KCl

This is a strong acid - strong base reaction. HCl is the strong acid and KOH is the strong base. 

H⁺ in the HCl and OH⁻ of the KOH pair up and make H₂O(l). 

K⁺ and Cl⁻ pair up to make KCl salt. 

Positive ion is K⁺ which has +1 charge and negative ion is Cl⁻ which has -1 charge. By switching the charges K⁺ gets 1 and Cl⁻ also gets 1. Hence, the salt should be KCl.

Balance equation is
HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq)

5 0

3 years ago

Read 2 more answers

Find the atomicity of water.

Flauer [41]

One molecule of water contains two atoms of hydrogen and one atom of oxygen, the atomicity of water is three.

4 0

2 years ago

Carbon has an atomic number of 6. This means it has 6 protons and 6 electrons. How many valence electrons does carbon have?

Varvara68 [4.7K]

Answer:

Explanation:

Carbon configuration- 2,4

Valence electrons means the outershell electrons

That means valence electrons=4

8 0

3 years ago

Which types of asexual reproduction could be seen

natita [175]

Answer:

Bacteria

Explanation:

On a piece of raw, fresh hamburger from the butcher's, bacteria are rapidly multiplying through asexual reproduction.

5 0

3 years ago

The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.

Mars2501 [29]

C: 0.012 mol.

<h3>Explanation</h3>

Start with 0.0020 moles of iodate ions ${\text{IO}_{3}}^{-}$ .

How many moles of iodine $\text{I}_2$ will be produced?

${\text{IO}_{3}}^{-}$ converts to $\text{I}_2$ in the first reaction. The coefficient in front of $\text{I}_2$ is three times the coefficient in front of ${\text{IO}_{3}}^{-}$ . In other words, each mole of ${\text{IO}_{3}}^{-}$ will produce three moles of $\text{I}_2$ . 0.0020 moles of ${\text{IO}_{3}}^{-}$ will convert to 0.0060 moles of $\text{I}_2$ .

How many moles of thiosulfate ions ${\text{S}_2\text{O}_3}^{2-}$ are required?

$\text{I}_2$ reacts with ${\text{S}_2\text{O}_3}^{2-}$ in the second reaction. The coefficient in front of $\text{I}_2$ is twice the coefficient in front of ${\text{S}_2\text{O}_3}^{2-}$ . How many moles of ${\text{S}_2\text{O}_3}^{2-}$ does each mole of $\text{I}_2$ consume? Two. 0.0060 moles of $\text{I}_2$ will be produced. As a result, $2 \times 0.0060 = 0.0120$ moles of ${\text{S}_2\text{O}_3}^{2-}$ will be needed.

6 0

2 years ago