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ira [324]
3 years ago
13

The density of quartz mineral was determined by adding a weighed piece to a graduated cylinder containing 50.3 mL water. After t

he quartz was submerged, the water level was 64.8 mL. The quartz piece weighed 38.9 g. What was the density of the quartz?
Chemistry
2 answers:
sergij07 [2.7K]3 years ago
8 0

<u>Answer:</u> The density of the quartz is 2.68 g/mL

<u>Explanation:</u>

We are given:

Volume of graduated cylinder = 50.3 mL

Volume of quartz + graduated cylinder = 64.8 mL

Volume of quartz = [64.8 - 50.3] mL = 14.5 mL

To calculate the density of substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Mass of quartz = 38.9 g

Volume of quartz = 14.5 mL

Putting values in above equation, we get:

\text{Density of quartz}=\frac{38.9g}{14.5mL}\\\\\text{Density of quartz}=2.68g/mL

Hence, the density of the quartz is 2.68 g/mL

olganol [36]3 years ago
6 0

Answer:

The density of the quartz is 2.68 g/mL

Explanation:

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3 years ago
the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t
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Answer:

m = 50.74 kg

Explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

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It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

Q=mc\Delta T

c is specific heat of water, c = 4.186 J/g°C

So,

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg

So, the mass of the sample is 50.74 kg.

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3 years ago
What effect does filtration have on water with a ph of 3?
creativ13 [48]

Answer:

None  

Step-by-step explanation:

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Hydrogen ions are so small that they pass through the pores of an ordinary filter.

Thus, ordinary filtration has no effect on the pH of water.

4 0
3 years ago
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
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The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

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1 year ago
Methyl violet is an indicator that changes color over a range from pH=0.0 to pH=1.6. What is Ka of methyl violet?
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it's basic in nature

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3 years ago
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