The density of quartz mineral was determined by adding a weighed piece to a graduated cylinder containing 50.3 mL water. After t
2 answers:
<u>Answer:</u> The density of the quartz is 2.68 g/mL
<u>Explanation:</u>
We are given:
Volume of graduated cylinder = 50.3 mL
Volume of quartz + graduated cylinder = 64.8 mL
Volume of quartz = [64.8 - 50.3] mL = 14.5 mL
To calculate the density of substance, we use the equation:
Mass of quartz = 38.9 g
Volume of quartz = 14.5 mL
Putting values in above equation, we get:
Hence, the density of the quartz is 2.68 g/mL
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Answer:- The Ka for the acid is .
Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:
HA(aq)\rightarrow H^+(aq) + A^-(aq)
Now, we make the ice table for this equation as:
HA(aq)\rightarrow H^+(aq) + A^-(aq)
I 0.25 0 0
C -X +X +X
E (0.25 - X) X X
where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.
X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.
Where, Ka is the acid ionization constant. Let's plug in the values.
Let's calculate the value of X first using the equation:
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on taking antilog ob above equation we get:
= 0.00195
So, X = 0.001195
Let's plug in this value of X in the equation:-
So, the value of Ka for butyric acid is .